Weld wire consumption

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Does anyone has weld wire consumption formula for .035 308 LSI Stainless Steel wire for MIG weldingI need to calculate theoritical usage .....is there guidelines for itThanks in advance
Reply:http://content.lincolnelectric.com/p...ure/c64000.pdfEd Conleyhttp://www.screamingbroccoli.com/MM252MM211 (Sold)Passport Plus & Spool gunLincoln SP135 Plus- (Gone to a good home)Klutch 120v Plasma cutterSO 2020 benderBeer in the fridge
Reply:Ingesting weld wire could be hazardous to one's health...MM350P/Python/Q300MM175/Q300DialarcHFHTP MIG200PowCon300SMHypertherm380ThermalArc185Purox oaF350CrewCab4x4LoadNGo utilitybedBobcat250XMT304/Optima/SpoolmaticSuitcase12RC/Q300Suitcase8RC/Q400Passport/Q300Smith op
Reply:you could try this, weigh the roll, do some welding and weigh it again, keep track of the time, and how many feet of weld u laid down. i dont know of a formula but this is another way to do it.Nothing Ever Got Done By Quitting, Never Give Up.
Reply:Go to this link and scroll all the way down to Section 8 "Calculating Filler Metal Consumption".  It will help you calculate your concumption based on the size wire you're using and the size weld you have, which is the only accurate way to calculate it.Good luck.http://www.esabonline.com/tools_of_t...k_complete.pdfWelding is my hobby, I just happen to get paid for it!
Reply:Yes, but you need to state your WFSFor exampleFirst you must find the area of your wire. Then Multiply by WFS. (I'll use 200 In/min for example). then multiply it by the density of your metal. (i just used the density of steel) then mulitply by 60 to get your units into pounds per hour Pi x (.035"/2)^2= .00096in^2 x 200in/min= .192in^3/min x.283lbs/in^3= .0543 lbs/min x 60min/1 hr= 3.26 lbs/hour. That is your deposition rate. --Gol'
Reply:Originally Posted by Go1lumYes, but you need to state your WFSFor exampleFirst you must find the area of your wire. Then Multiply by WFS. (I'll use 200 In/min for example). then multiply it by the density of your metal. (i just used the density of steel) then mulitply by 60 to get your units into pounds per hour Pi x (.035"/2)^2= .00096in^2 x 200in/min= .192in^3/min x.283lbs/in^3= .0543 lbs/min x 60min/1 hr= 3.26 lbs/hour. That is your deposition rate.