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Is there a formula to calculate the number of rods needed for arc welding if given the pipe diameter, rod size, regulations,and number of joints
Reply:I'd think not...Any calculation would have to have a set amount of weldment being burned each run, which is impossible to do. You generally don't input 100% of a electrode into the weld (spatter, tip etc.) Yes there are electrodes which burn 100% efficiently and more, but, i'd think it would be too difficult to judge.Without a constant input of weld it can't be calculated for me prior to any welding...Last edited by Jee; 11-08-2007 at 03:10 PM.Metaltrades.co.uk
Reply:To a certian degree. You need to find the cross sectional area of of the "weld" then find the volume. Multiply it by the density of steel which is .283 lbs/cubic inch. That will give you the weight of your weld. Then find the price per pound for your electrode. then you need to factor in process effeciancy. with SMAW it's only like somthing of 60% of the electrode actually gets deposited due to stub loss and spatter. that should get you in ball park rang for the pounds of electrodes you'll need for a given weld. --Gol'
Reply:Originally Posted by JeeI'd think not...Any calculation would have to have a set amount of weldment being burned each run, which is impossible to do. You generally don't input 100% of a electrode into the weld (spatter, tip etc.) Yes there are electrodes which burn 100% efficiently and more, but, i'd think it would be too difficult to judge.Without a constant input of weld it can't be calculated for me prior to any welding...
Reply:In "The procedure handbook for arc welding" by Lincoln Electric, it lists "electrode required (lb/ft)" for the weld procedures. It also sez its the amount of rod to order, not actual rod put into the weld. For example, 3/16" fillet It sez use .128 lb per foot of weld for a 5/32 fillet.So yes there is information.David Real world weldin. When I grow up I want to be a tig weldor.
Reply:Try pulling out a SMAW calculator Maybe it could help also weld it like you own it
Reply:talk to your supplier, they will have this info for you
Reply:Just keep more than you plan on using on hand, never failed anyone methinks.
Reply:Originally Posted by David RIn "The procedure handbook for arc welding" by Lincoln Electric, it lists "electrode required (lb/ft)" for the weld procedures. It also sez its the amount of rod to order, not actual rod put into the weld. For example, 3/16" fillet It sez use .128 lb per foot of weld for a 5/32 fillet.So yes there is information.David
Reply:Originally Posted by Go1lumThere isn't any process i know of that has 100 % effeciancy. Theoreticaly it's possible but not literally. Even with a spray transfer mig the effeciacy is only up in the high 90's for effeciancy. |
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